PHALIN THAKKAR

What linear analyzer readings leave out

Can intensity readings recover a complete polarisation state?

Note 11 · Research extension

Analytical result · Hypothetical examples are not physical measurements.

A calibrated ideal linear analyzer measures:

I(a)=12[S0+S1cos⁡2a+S2sin⁡2a].I(a)=\frac12[S_0+S_1\cos2a+S_2\sin2a].

S0 describes total intensity. S1 and S2 describe linear polarisation components. S3, which contains circular polarisation information, does not appear.

Consider three states with the same total intensity S0 = 1:

- Unpolarized: S = (1, 0, 0, 0).

- One circular handedness: S = (1, 0, 0, +1).

- The opposite handedness: S = (1, 0, 0, −1).

Every rotating linear analyzer returns ½ for all three. The handedness sign convention does not affect this conclusion.

Consequently, equal readings at every linear setting do not establish that the input is unpolarized. A general elliptical state can reveal a linear component and its azimuth, but linear analyzer readings do not determine its full state.

Additional calibrated optics, such as a waveplate before the analyzer, can convert otherwise inaccessible components into measurable intensity variation.

The current hidden direction model assumes fully linear input. Extending it to a full state reconstruction is a further question, not a completed laboratory result.

Continue the reasoning

Finding the hidden direction

Wilkinson and colleagues: Complete Stokes vector analysis with a compact, portable rotating waveplate polarimeter. A reading reference showing how calibrated optics can recover additional components, not a publication by Phalin.

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